Question

How do you solve `x^2-5x>0`?

Answer 1

`x^2-5x>0`
could be written as
`x^2> 5x`

Case 1: x<0
then `x^2>0` and `5x<0`
So the inequality is true for all values of `x<0`

**Case 2: x>=0#** Dividing both sides by #x# gives #x>5#

Complete Solution
`x<0` or `x>5`