# How do you solve  x^2-5x>0 ?

May 7, 2015

${x}^{2} - 5 x > 0$
could be written as
${x}^{2} > 5 x$

Case 1: x<0
then ${x}^{2} > 0$ and $5 x < 0$
So the inequality is true for all values of $x < 0$

**Case 2: x>=0** Dividing both sides by x gives x>5#

Complete Solution
$x < 0$ or $x > 5$