How do you solve #x^2 + 5x = 0#?

2 Answers
Apr 21, 2018

Answer:

#x_1 = 0#
#x_2 = -5#

Explanation:

#x^2 + 5x = 0#
#x(x+5) = 0#

By the null factor law either #x# or #x+5# must be equal to #0#.

#x_1 = 0#
#x_2 = -5#

Apr 21, 2018

Answer:

#x=-5" or "x=0#

Explanation:

#"take out a "color(blue)"common factor "x#

#rArrx(x+5)=0#

#"equate each of the factors to zero and solve for x"#

#rArrx=0#

#x+5=0rArrx=-5#