# How do you solve x^2-5x+6=0  by factoring?

Since the $6$ has a $+$-sign you're looking for two factors of $6$ that add up to $- 5$
These can only be $- 2 \mathmr{and} - 3$ so the factoring goes:
$\left(x - 2\right) \left(x - 3\right) = 0 \to x = 2 \mathmr{and} x = 3$