How do you solve x^2 - 6x + 4 = 0x26x+4=0 using the quadratic formula?

1 Answer
Mar 3, 2016

x = 3 +- sqrt5x=3±5

Explanation:

y = x^2 - 6x + 4 = 0y=x26x+4=0
D = d^2 = b^2 - 4ac = 36 - 16 = 20D=d2=b24ac=3616=20 --> d = +- 2sqrt5d=±25
x = -b/(2a) +- d/(2a) = 6/2 +- (2sqrt5)/2 = 3 +- sqrt5x=b2a±d2a=62±252=3±5