# How do you solve x^2=-9?

$= \pm 3 \setminus i$
${x}^{2} = - 9$
$x = \pm \sqrt{- 9}$
$x = \pm \sqrt{9 \times - 1}$
$= \pm \sqrt{9} \sqrt{- 1}$
$= \pm 3 \setminus i$