How do you solve #x/2=sqrt(3x)#?

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Answer 1 · 2015-08-19T12:50:33

The solutions are
#color(blue)(x=0#

#color(blue)(x=12#

#x/2=sqrt(3x)#

Squaring both sides
#(x/2)^2=(sqrt(3x))^2#

#x^2/4=3x#

#x^2=3x*4#

#x^2=12x#

#x^2-12x=0#

Factorising the expression:

#x(x-12)=0#

Solution 1:
#color(blue)(x=0#

Solution 2
#x-12=0#
#color(blue)(x=12#