How do you solve #x/2=sqrt(3x)#?

1 Answer
Aug 19, 2015

Answer:

The solutions are
#color(blue)(x=0#

#color(blue)(x=12#

Explanation:

#x/2=sqrt(3x)#

Squaring both sides
#(x/2)^2=(sqrt(3x))^2#

#x^2/4=3x#

#x^2=3x*4#

#x^2=12x#

#x^2-12x=0#

Factorising the expression:

#x(x-12)=0#

Solution 1:
#color(blue)(x=0#

Solution 2
#x-12=0#
#color(blue)(x=12#