# How do you solve -x^2 - x + 6 < 0?

##### 1 Answer
May 4, 2015

The given quadratic inequality is same as ${x}^{2} + x - 6 > 0$. Factorise it (x+3)(x-2)>0

It has two solutions, x+3>0 and x-2>0, Or x+3<0 and x-2<0.

In the first case x>-3 and x>2 which means x>2. If x>2, it would automatically mean x>-3

Like wise in the second case, it would mean x<-3. On the number line the inequality would be represented by x>2 and x<-3