Question

How do you solve `(x-2)/(x+6)=(x+4)/(x+2)`?

Answer 1

You can get rid of the denominators by using the property `a/b = m/n -> b xx m = a xx n`

Explanation:

`(x + 6)(x + 4) = (x - 2)(x + 2)`

`x^2 + 6x + 4x + 24 = x^2 - 2x + 2x - 4`

`x^2 - x^2 + 10x + 28 = 0`

`10x = -28`

`x = -14/5`

Hopefully this helps.