# How do you solve #x^3 -3x^2 +16x -48 = 0#?

##### 1 Answer

Feb 16, 2017

#### Answer:

#### Explanation:

From sign changes in the coefficients, the equation has utmost 3

positive roots,There are no changes in sign,

when x is changed to

The cubic is 0 at x = 0. So, it becomes

The other solutions are from by

graph{(x-3)(x^2+16) [2, 4, -500, 500]} 0, -500, 500]}

Not to scale. It is large y vs small x, for approximating the solution.