How do you solve #(x-3)/4=2#?
1 Answer
Jul 23, 2016
x = 11
Explanation:
If we multiply both sides of the equation by 4 then we eliminate the fraction.
#color(red)cancel(4)^1xx(x-3)/(color(red)cancel(4)^1)=color(red)(4)xx2# we are now left with : x - 3 = 8
Add 3 to both sides to solve for x
#x-cancel(3)+cancel(3)=8+3#
#rArrx=11#
