# How do you solve x^3 − 5x^2 − 36x + 180 = 0?

May 30, 2016

You can solve this one easily by factoring.

#### Explanation:

${x}^{2} \left(x - 5\right) - 36 \left(x - 5\right) = 0$

$\left({x}^{2} - 36\right) \left(x - 5\right) = 0$

${x}^{2} = 36 \mathmr{and} x = 5$

$x = \pm 6 \mathmr{and} 5$

Hopefully this helps!