How do you solve #x-6 = (x-4)^(1/2)# and find any extraneous solutions?
Square both sides giving:
Remember than the index of
We cannot find the square root of a negative number, so
To get rid of the square root, you need to square both sides. A common error is to square each of the terms of the left, inside of treating them as a binomial.
'Find factors of 40 which add (because of +40) to give 13.'
The signs will be the same, (because of +40) they are both minus (because of -13).