How do you solve # x/(x-2) - 2/(x-2)= - 2#?

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Answer 1 · 2016-02-13T22:58:16

No solution

#x/(x-2)-2/(x-2)=-2#

#(x-2)/(x-2)=-2#

#1=2#

No solution

Let's take other way:

#x/(x-2)-2/(x-2)=-2#

Multiplying everithing by (x-2) , but taking in acount that #x!=2):

#x-2=2(x-2)#

#x-2=2x-4)#

#-x=-2#

#x=2#, which is not valid, beacuse when we multiplied by x-2 excluded 2 as solution.