# How do you solve x-y=2 and 3x+y=-10?

Jun 21, 2016

By substitution.

#### Explanation:

$x = 2 + y$

$3 \left(2 + y\right) + y = - 10$

$6 + 3 y + y = - 10$

$4 y = - 16$

$y = - 4$

$x - \left(- 4\right) = 2$

$x = 2 - 4$

$x = - 2$

Thus, the solution set is $\left\{- 2 , - 4\right\}$.

Hopefully this helps!