How do you solve #x+y= -3# and #x+y=3#?

1 Answer
Aug 23, 2015

Answer:

#{(x = O/), (y = O/) :}#

Explanation:

Your system of equations will have no solution.

You can think about this in two ways.

Notice that you have #x+y# on the left side of both equations, but that the right side is different. The first equation has

#x+y = -3#

and the second equation has

#x+y = 3#

If you try to replace #x+y# from the first equation into the second, you will get

#3 != -3#

An alternative approach is to notice that you're dealing with the equations of two lines. When you're solving a system of equations, you're essentially looking for the point in which those lines intersect.

In your case, these lines will never intersect because they are parralel lines.

graph{(y+x-3)(y+x+3)=0 [-10, 10, -5, 5]}