How do you solve #y=x^2+3#?

1 Answer
May 18, 2018

Answer:

As such, you can not 'solve' this

Explanation:

Consider the parent graph of #y=x^2# This is of general shape #uu# and the bottom of the curved part (vertex) ist at the origin #(x,y)->(0,0)#

Now if we add 3 we are effectively 'lifting' the whole thing up by 3. So now the vertex is still on the on the y-axis but at the point #(x,y)->(0,3)# instead of #(0,0)#

Mathematically:

The graph crosses the y-axis at #x=0# so by substitution:

#y=x^2+3 color(white)("dddd")-> color(white)("dddd")y=(0)^2+3 = 3#