How do you tell whether the graph opens up or down, find the vertex and the axis of symmetry of #y=5(x+5)(x-2)#?

1 Answer
Dec 22, 2017

#y=5(x+5)(x-2)#
opens upward
and has an axis of symmetry #x=-1 1/2#

Explanation:

A quadratic opens upward if the coefficient of #x^2# is greater than zero,
and downward if the coefficeint of #x^2# is less than zero.

An expansion of #5(x+5)(x-2)# would have the term #5x^2#
That is the coefficient of #x^2# would be #5#.
Since this is greater than zero the graph would open upward.

For a quadratic in standard form which crosses the X-axis, the axis of symmetry is
#color(white)("XXX")x=c#
where #c# is the midpoint value between the x-intercept values.

The x-intercept values are the values of #x# when #y=0#

In this case (obviously) #y=0# if #x=-5# or #x=+2#

The midpoint between #-5# and #+2# is #-1 1/2#
so the axis of symmetry is
#color(white)("XXX")x=-1 1/2#