Question

How do you use factoring to solve this equation `3x^2-12x=-12`?

Answer 1

Rewrite `3x^2-12x = -12`
as
`3x^2-12x+12 = 0`

Factor out the constant `3`
`3(x^2-4x+4) = 0`

Factor the expression
`3(x-2)(x-2) = 0`

This can only be true if `(x-2) = 0`

Therefore `x=2`