# How do you use find the zeroes of f(x)=(x+1)^2(x+7)?

Jul 29, 2016

Zeros of $f \left(x\right) = {\left(x + 1\right)}^{2} \left(x + 7\right)$ are $- 1$ and $- 7$.

#### Explanation:

As the function is product of monomials, it is easier to find zeros of $f \left(x\right)$.

Zeros of a function, say of $x$, are those values of $x$, for which $f \left(x\right)$ becomes zero.

As $f \left(x\right)$ is a product of monomials. if any monomial becomes zero, the function becomes zero.

Hence zeros are given by $x + 1 = 0$ i.e. $x = - 1$ and

$x + 7 = 0$ i.e. $x = - 7$

Hencem zeros of $f \left(x\right) = {\left(x + 1\right)}^{2} \left(x + 7\right)$ are $- 1$ and $- 7$.