How do you use FOIL to multiply #(sqrt2-sqrt3)(sqrt2-sqrt3) #?

1 Answer
Alan P.
Jun 4, 2015

#(color(red)(sqrt(2))color(blue)(-sqrt3))(color(green)(sqrt(2))-color(orange)(sqrt(3)))#

F irst terms: #color(red)(sqrt(2))xxcolor(green)(sqrt(2)) = 2#
O utside terms: #color(red)(sqrt(2))xxcolor(orange)((-sqrt(3))) = -sqrt(6)#
I nside terms: #color(blue)((-sqrt(3)))xxcolor(green)(sqrt(2)) = -sqrt(6)#
L ast terms: #color(blue)((-sqrt(3)))xxcolor(orange)((-sqrt(-3))) = 3#

Sum of FOIL
#color(white)("XXXX")##=5 - 2sqrt(6)#

Related questions
See all questions in Multiplication of Polynomials by Binomials
Impact of this question
892 views around the world
You can reuse this answer
Creative Commons License