# How do you use limits to find the area between the curve y=x^2+6x and the x axis from [0,4]?

$A = {\int}_{0}^{4} {x}^{2} + 6 x \mathrm{dx} = {x}^{3} / 3 + 3 {x}^{2} {|}_{0}^{4} = \frac{208}{3} {\text{ units}}^{2}$