How do you use Pascal's triangle to calculate the binomial coefficient of #((7), (3))#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer Cem Sentin Dec 9, 2017 #C(7, 3)=35# Explanation: #C(7, 3)=(7!)/((7-3)!*3!)=(7!)/(4!*3!)=(4!*5*6*7)/(4!*6)=35# Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 2472 views around the world You can reuse this answer Creative Commons License