How do you use quadratic formula to solve #2x^2 + 4x + 2 = 0#?

1 Answer
Jun 12, 2015

Answer:

The solution for this equation is
# color(red)(x = -1#

Explanation:

# 2x^2+4x+2#
The equation is of the form #color(blue)(ax^2+bx+c=0# where:
#a=2, b=4, c=2#

The Discriminant is given by:
#Delta=b^2-4*a*c#
# = (4)^2-(4*2*2)#
# = 16 - 16=0#
As #Delta=0# then there is only one solution.

The solution is found using the formula
#x=(-b+-sqrtDelta)/(2*a)#

As #Delta = 0#, #x = ((-4)+-sqrt(0))/(2*2) = -4/4 = -1#
So , #x = -1#