How do you use the chain rule to differentiate #y=root3(4x-1)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Gerardina C. · Shwetank Mauria Jan 27, 2017 #y'=4/(3root(3)((4x-1)^2))# Explanation: #y'=1/(3root(3)((4x-1)^2))*4=4/(3root(3)((4x-1)^2))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1280 views around the world You can reuse this answer Creative Commons License