How do you use the difference of two squares formula to factor #9/x^6 - 64y^2#?

2 Answers
Jun 9, 2018

Answer:

#(3/x^3-8y)(3/x^6+8y)#

Explanation:

Using the formula
#(a-b)(a+b)=a^2-b^2#

we get

#(3/x^3-8y)(3/x^4+8y)#

Jun 9, 2018

Answer:

#(3/x^3-8y)(3/x^3+8y)#

Explanation:

#•color(white)(x)a^2-b^2=(a-b)(a+b)larrcolor(blue)"difference of squares"#

#9/x^6=(3/x^3)^2rArra=3/x^3#

#64y^2=(8y)^2rArrb=8y#

#9/x^6-64y^2=(3/x^3-8y)(3/x^3+8y)#