Question

How do you use the important points to sketch the graph of `f(x)=x^2 + 6x - 7`?

Answer 1

`x=[-b]/(2a)` gives the `x` coordinate for the line of symmetry

`x=[-6]/2=-3`

Now you know the graph is symmetrical around the line `x=-3` make a table to generate coordinates.

Use `x` values `1,0,-1,-2,-3,-4,-5,-6,-7` put these into the equation `y=x^2+6x-7`

When you get the coordinates it will create a `uu` shaped parabola as the `x^2` is positive and remember to join the points freehand not with a ruler.