Question

How do you use the important points to sketch the graph of `y=3x^2-24x+10`?

Answer 1

This parabola cuts y-axis x = 0 at ( 0, 10 ). It cuts x-axis y = 0 at (4, `+-(1/3)sqrt114 )`. Lowest point vertex: ( 4, `-`38 ). Axis of symmetry: x = 4. It rises above without limit.

Explanation:

The equations `y = ax^2 + bx + c and x = ay^2 + by + c` represent parabolas,with axis parallel to y-axis and x-axis, respectively.