# How do you use the important points to sketch the graph of #y=x^2+6x+5#?

##### 1 Answer

Mar 24, 2016

The vertex V of this parabola is

#### Explanation:

The equation can be rearranged as

This represents a parabola with vertex at

The parameter for size a =

The curve is above this vertex and is symmetrical about its axis

Put y= o.and solve

The focus

The directrix #y--17/4) is equidistant below the vertex and is parallel to the x-axis..

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