Question

How do you use the point (-1,1) on the terminal side of the angle to evaluate the six trigonometric functions?

Answer 1

Find values of trig functions

Explanation:

On the trig unit circle, the point (-1, 1) is located on the arc
`t = (3pi)/4` or arc `t = -(5pi)/4` (Co-terminal).
With `t = (3pi)/4` the unit circle and the trig table of special arcs give the 6 values of the 6 trig functions:
`sin t = sqrt2/2`
`cos t = - sqrt2/2`
`tan t = sin/(cos) = - 1`
`cot t = 1/(tan) = - 1`
`sec t = - 2/sqrt2 = - sqrt2`
`csct = 2/sqrt2 = sqrt2`