How do you use the quadratic formula to solve 9x^2-6x+37=0?

1 Answer
Dec 20, 2016

x = 1/3+-2i

Explanation:

9x^2-6x+37 = 0

is in the form:

ax^2+bx+c = 0

with a=9, b=-6 and c=37

This has zeros given by the quadratic formula:

x = (-b +-sqrt(b^2-4ac))/(2a)

color(white)(x) = (6+-sqrt((-6)^2-4(9)(37)))/(2(9))

color(white)(x) = (6+-sqrt(36-36(37)))/18

color(white)(x) = (6+-sqrt(36(1-37)))/18

color(white)(x) = (6+-sqrt(-36^2))/18

color(white)(x) = (6+-36i)/18

color(white)(x) = 1/3+-2i