How do you use the quadratic formula to solve 9x^2-6x+37=0?
1 Answer
Dec 20, 2016
Explanation:
9x^2-6x+37 = 0
is in the form:
ax^2+bx+c = 0
with
This has zeros given by the quadratic formula:
x = (-b +-sqrt(b^2-4ac))/(2a)
color(white)(x) = (6+-sqrt((-6)^2-4(9)(37)))/(2(9))
color(white)(x) = (6+-sqrt(36-36(37)))/18
color(white)(x) = (6+-sqrt(36(1-37)))/18
color(white)(x) = (6+-sqrt(-36^2))/18
color(white)(x) = (6+-36i)/18
color(white)(x) = 1/3+-2i