# How do you use the quadratic formula to solve #x^2-2x+2=0#?

##### 1 Answer

Aug 16, 2016

This quadratic has zeros

#### Explanation:

#x^2-2x+2=0#

This is in the form

It has zeros given by the quadratic formula:

#x = (-b+-sqrt(b^2-4ac))/(2a)#

#=(2+-sqrt((-2)^2-4(1)(2)))/(2*1)#

#=(2+-sqrt(4-8))/2#

#=(2+-sqrt(-4))/2#

#=(2+-(sqrt(4))i)/2#

#=(2+-2i)/2#

#=1+-i#