# How do you use the quotient rule to differentiate 3/(3x+3)?

$\frac{d}{\mathrm{dx}} \left(\frac{3}{3 x + 3}\right) = - \frac{1}{x + 1} ^ 2$
$\frac{d}{\mathrm{dx}} \left(\frac{3}{3 x + 3}\right) = \frac{d}{\mathrm{dx}} \left(\frac{1}{x + 1}\right) = \frac{d}{\mathrm{dx}} {\left(x + 1\right)}^{- 1} = \left(- 1\right) {\left(x + 1\right)}^{- 2} = - 1 {\left(x + 1\right)}^{2}$