Question

How do you use the quotient rule to differentiate `3/(3x+3)`?

Answer 1

`d/dx (3/(3x+3)) = -1/(x+1)^2`

Explanation:

`d/dx (3/(3x+3)) = d/dx (1/(x+1)) = d/dx (x+1)^(-1) = (-1)(x+1)^(-2) =-1(x+1)^2`