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How do you use the unit circle to derive $sin (2 π - θ)$ $sin(2pi-theta)$ ?

1 Answer

Feb 27, 2017

sin t

Explanation:

$sin (2 π - t) = sin (- t + 2 π) = sin (- t) = - sin t$ $sin (2pi - t) = sin (- t + 2pi) = sin (- t) = - sin t$

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