How do you verify the identity #(2+cscthetasectheta)/(cscthetasectheta)=(sintheta+costheta)^2#?

1 Answer
Sep 1, 2016

You will need the following identities to prove this identity.

#cscbeta = 1/sinbeta#

#secbeta = 1/cosbeta#

#sin^2beta + cos^2beta = 1#

Simplify the left-hand side and expand the right-hand side.

#(2 + 1/sintheta xx 1/costheta)/(1/sintheta xx 1/costheta) = sin^2theta+ 2sinthetacostheta + cos^2theta#

#(2 + 1/(sinthetacostheta))/(1/(sinthetacostheta)) = 1 + 2sinthetacostheta#

#((2sinthetacostheta + 1)/(sinthetacostheta))/(1/(sinthetacostheta)) = 1 + 2sinthetacostheta#

#(2sinthetacostheta+ 1)/(sin thetacostheta) xx (sinthetacostheta)/1 = 1+ 2sinthetacostheta#

#2sinthetacostheta + 1 = 1 + 2sinthetacostheta#

Identity proved!!

Hopefully this helps!