How do you write #2x - 3y > 7# in slope intercept form?

1 Answer
Aug 7, 2015

The boundary can be written in slope-intercept form giving
#color(white)("XXXX")##y < 2/3x+(-7/3)#

Explanation:

given #2x-3y > 7#

adding #3y# to both sides
#color(white)("XXXX")##2x > 3y+7#

subtracting 7 from both sides
#color(white)("XXXX")##2x-7 > 3y#

dividing both sides by #3#
#color(white)("XXXX")##2/3x-7/3 > y#

Reversing the sides
#color(white)("XXXX")##y < 2/3-7/3#

or (in explicit slope-intercept form
#color(white)("XXXX")##y < (2/3)x + (-7/3)#
where the boundary line has a slope of #2/3# and a y-intercept of #(-7/3)#