# How do you write (3+2i)+(5-i)+6i in standard form?

$7 i + 8$
$3 + 2 i + 5 - i + 6 i$
$2 i - i + 6 i + 8$
$i \left(2 - 1 + 6\right) + 8$
$7 i + 8$