How do you write #3x^2(2x^3 – 4x^2)# in standard form?

1 Answer

Answer:

#6x^5-12x^4#

Explanation:

The formula for expanding #a(b+c)# is #ab+ac#. In this exanple #a=3x^2; b=2x^3;# and #c=-4x^2#.

That leaves us with #3x^2(2x^3)+3x^2(-4x^2)#.

To multiply #ax^b# by #cx^d#, we do #(a*c)x^(b+d)#. Putting our values in, we get #(3*2)x^(2+3)= 6x^5#. Now by doing #3x^2(-4^2)#, we get #(3*-4)x^(2+2)=(-12)x^4=-12x^4#.

By adding both values together we get #6x^5-12x^4#.