# How do you write (3x^2 + 7) – (x^2 – 6x + 4)  in standard form?

##### 1 Answer
May 30, 2016

$2 {x}^{2} + 6 x + 3$

#### Explanation:

The minus sign in front of $- \left({x}^{2} - 6 x + 4\right)$ means that you multiply everything inside the brackets by $\left(- 1\right)$

So $\textcolor{b r o w n}{- \left({x}^{2} - 6 x + 4\right) \text{ "color(blue)(->" } - {x}^{2} + 6 x - 4}$

$\textcolor{g r e e n}{\text{Putting it all together}}$

$\textcolor{b r o w n}{\left(3 {x}^{2} + 7\right) - \left({x}^{2} - 6 x + 4\right) \text{ "color(blue)(->" } 3 {x}^{2} + 7 - {x}^{2} + 6 x - 4}$

$\textcolor{g r e e n}{\text{Grouping like terms}}$

$\left(3 {x}^{2} - {x}^{2}\right) + \left(+ 6 x\right) + \left(7 - 4\right) \text{ "->" } 2 {x}^{2} + 6 x + 3$