How do you write #(3x^2 + 7) – (x^2 – 6x + 4) # in standard form?

1 Answer
May 30, 2016

#2x^2+6x+3#

Explanation:

The minus sign in front of #-(x^2-6x+4)# means that you multiply everything inside the brackets by #(-1)#

So #color(brown)(-(x^2-6x+4)" "color(blue)(->" "-x^2+6x-4)#

#color(green)("Putting it all together")#

#color(brown)((3x^2+7)-(x^2-6x+4)" "color(blue)(->" "3x^2+7-x^2+6x-4)#

#color(green)("Grouping like terms")#

#(3x^2-x^2)+(+6x)+(7-4)" "->" "2x^2+6x+3#