How do you write #-3x+2y=7# in slope-intercept form? What is the slope and #y#-intercept?

1 Answer
Sep 6, 2017

See a solution process below:

Explanation:

The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

First, add #color(red)(3x)# to each side of the equation:

#color(red)(3x) - 3x + 2y = color(red)(3x) + 7#

#0 + 2y = 3x + 7#

#2y = 3x + 7#

Now, divide each side of the equation by #color(red)(2)#:

#(2y)/color(red)(2) = (3x + 7)/color(red)(2)#

#(color(red)(cancel(color(black)(2)))y)/cancel(color(red)(2)) = (3x)/color(red)(2) + 7/color(red)(2)#

#y = color(red)(3/2)x + color(blue)(7/2)#

Therefore:

  • The slope is: #color(red)(m = 3/2)#

  • The #y#-intercept is: #color(blue)(b = 7/2)# or #(0, color(blue)(7/2))#