How do you write $- 3 x - 8 y = 10$ $-3x-8y=10$ into slope intercept form?

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How do you write $- 3 x - 8 y = 10$ $-3x-8y=10$ into slope intercept form?

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Answer 1 · 2015-08-29T17:02:53

$y = - \frac{3}{8} x - \frac{5}{4}$ $y = -3/8x - 5/4$

Explanation:

Given $- 3 x - 8 y = 10$ $-3x-8y = 10$

$- 8 y = + 3 x + 10$ $-8y = +3x + 10$

$y = - \frac{3}{8} x + \frac{10}{8} = (- \frac{3}{8}) x + (- \frac{5}{4})$ $y = -3/8x + 10/8 = (-3/8)x + (-5/4)$
$XXXXXX$ $color(white)("XXXXXX")$ which is slope intercept form
$XXXXXX$ $color(white)("XXXXXX")$ with slope $= - \frac{3}{8}$ $=-3/8$ and y-intercept $= - \frac{5}{4}$ $=-5/4$

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How do you write $- 3 x - 8 y = 10$ $-3x-8y=10$ into slope intercept form?

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How do you write -3x-8y=10−3x−8y=10-3x-8y=10 into slope intercept form?

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Explanation:

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How do you write $- 3 x - 8 y = 10$ $-3x-8y=10$ into slope intercept form?