# How do you write 44^(1/6) in radical form?

Feb 28, 2017

## $\setminus \sqrt[6]{44}$

#### Explanation:

Template standard: given format...

## ${a}^{\frac{b}{c}}$

converting to radical format generates the form

## $\setminus \sqrt[c]{{a}^{b}}$

Please note that this is not a square root! It is a root function that varies depending on the value of $c$.

You are given the problem ${44}^{\frac{1}{6}}$. Based on the template, the respective variables are as follows:
$a = 44$, $b = 1$, $c = 6$
Now applying this to the radical format:

## $\setminus \sqrt[c]{{a}^{b}} \setminus \leftrightarrow \setminus \sqrt[6]{{44}^{1}}$

Since anything to the ${1}^{t h}$ power is the number itself, your answer is...