How do you write #49x^2 – 56x + 16# in factored form?

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Answer 1 · 2018-03-24T17:45:28

#(7x-4)(7x-4)#
or
#(7x-4)^2#

To factor #49x^2-56x+16#

We factor the 1st and 3rd terms

#1x*49x#
#7x*7x#

and

#1*16#
#2*8#
#4*4#

Looking at the trinomial we know the second sign is positive so we will be adding the values of the factors

#7*4 = 28#
#7*4 =28#

#28+28 = 56#

Since the first sign is negative and we are adding we need the signs for both binomials to be negative

#(7x-4)(7x-4)#