How do you write $49x^2 – 56x + 16$ in factored form?

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Answer 1 · 2018-03-24T17:45:28

$(7x-4)(7x-4)$
or
$(7x-4)^2$

To factor $49x^2-56x+16$

We factor the 1st and 3rd terms

$1x*49x$
$7x*7x$

and

$1*16$
$2*8$
$4*4$

Looking at the trinomial we know the second sign is positive so we will be adding the values of the factors

$7*4 = 28$
$7*4 =28$

$28+28 = 56$

Since the first sign is negative and we are adding we need the signs for both binomials to be negative

$(7x-4)(7x-4)$

How do you write 49x^2 – 56x + 1649x^2 – 56x + 16 in factored form?