# How do you write (4m+8)^2 in standard form?

May 16, 2018

$16 {m}^{2} + 64 m + 64$

#### Explanation:

Start by Writing $\left(4 m + 8\right)$ twice
${\left(4 m + 8\right)}^{2} = \left(4 m + 8\right) \left(4 m + 8\right)$

Each Term in the first parenthesis is to be distributed into the second parenthesis.
$= 4 m \left(4 m + 8\right) + 8 \left(4 m + 8\right)$
$= 16 {m}^{2} + 32 m + 32 m + 64$
$= 16 {m}^{2} + 64 m + 64$