How do you write ${(4 m + 8)}^{2}$ $(4m+8)^2$ in standard form?

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How do you write ${(4 m + 8)}^{2}$ $(4m+8)^2$ in standard form?

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Answer 1 · 2018-05-16T16:51:33

$16 m^{2} + 64 m + 64$ $16m^2 + 64m + 64$

Explanation:

Start by Writing $(4 m + 8)$ $(4m + 8)$ twice
${(4 m + 8)}^{2} = (4 m + 8) (4 m + 8)$ $(4m+8)^2 = (4m + 8)(4m+8)$

Each Term in the first parenthesis is to be distributed into the second parenthesis.
$= 4 m (4 m + 8) + 8 (4 m + 8)$ $= 4m(4m + 8) + 8(4m + 8)$
$= 16 m^{2} + 32 m + 32 m + 64$ $= 16m^2 + 32m + 32m + 64$
$= 16 m^{2} + 64 m + 64$ $= 16m^2 + 64m + 64$

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How do you write ${(4 m + 8)}^{2}$ $(4m+8)^2$ in standard form?

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