# How do you write 7/ x^-2  with positive exponents?

Jan 7, 2016

You should get $7 {x}^{2}$

#### Explanation:

You need to change "floor" and send $x$ from the ground to the first changing the sign of the exponent from $-$ to $+$; so:
$\frac{7}{x} ^ \left(- 2\right) = 7 {x}^{\textcolor{red}{+ 2}}$

Jan 7, 2016

$7 \cdot {x}^{2}$

#### Explanation:

The Exponent properties tell us that:

${a}^{-} n = \frac{1}{{a}^{n}}$

then:

$\frac{7}{{x}^{-} 2} = \frac{7}{\frac{1}{x} ^ 2} =$

with $x \ne 0$

$= \frac{{x}^{2} \cdot 7}{\cancel{{x}^{2}} \cdot \left(\frac{1}{\cancel{{x}^{2}}}\right)} = 7 {x}^{2}$