How do you write $8x^3+27$ in factored form?

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Answer 1 · 2015-09-15T19:38:26

It is $(2x)^3+3^3=(2x+3)*(4x^2-6x+9)$

We use the following identity

$a^3+b^3=(a+b)(a^2-ab+b^2)$

where $a=2x$ and $b=3$

hence we have that

$(2x)^3+3^3=(2x+3)*(4x^2-6x+9)$

How do you write 8x^3+278x^3+27 in factored form?