# How do you write 8x^3+27 in factored form?

It is ${\left(2 x\right)}^{3} + {3}^{3} = \left(2 x + 3\right) \cdot \left(4 {x}^{2} - 6 x + 9\right)$

#### Explanation:

We use the following identity

${a}^{3} + {b}^{3} = \left(a + b\right) \left({a}^{2} - a b + {b}^{2}\right)$

where $a = 2 x$ and $b = 3$

hence we have that

${\left(2 x\right)}^{3} + {3}^{3} = \left(2 x + 3\right) \cdot \left(4 {x}^{2} - 6 x + 9\right)$