# How do you write a cubic polynomial function with zeros -3, 2, and 1?

Nov 24, 2016

#### Answer:

$f \left(x\right) = \left(x + 3\right) \left(x - 2\right) \left(x - 1\right) = {x}^{3} - 7 x + 6$

#### Explanation:

Multiply together linear factors with each of these zeros:

$f \left(x\right) = \left(x + 3\right) \left(x - 2\right) \left(x - 1\right) = {x}^{3} - 7 x + 6$

Any polynomial in $x$ with these zeros will be a multiple (scalar or polynomial) of this $f \left(x\right)$.