How do you write a polynomial function with minimum degree whose zeroes are -1, 2, 3i? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Cem Sentin Mar 29, 2018 x^4-x^3+7x^2-9x-18 Explanation: If 3i is zero of this polynomial, -3i is also zero of it. Hence P(x)=(x-(-1))(x-2)(x-3i)(x-(-3i)) =(x+1)(x-2)(x-3i)(x+3i) =(x^2-x-2)(x^2+9) =x^4-x^3+7x^2-9x-18 Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of 10+6i? How do I find the complex conjugate of 14+12i? What is the complex conjugate for the number 7-3i? What is the complex conjugate of 3i+4? What is the complex conjugate of a-bi? See all questions in Complex Conjugate Zeros Impact of this question 2874 views around the world You can reuse this answer Creative Commons License