# How do you write a standard form equation for the hyperbola with #y^2 - 4y - 4x^2 + 8x = 4#?

##### 2 Answers

#### Answer:

The equation is

#### Explanation:

The general equation for a hyperbola is

or

Here, we have

Complete the square

Dividing by

The center is

graph{((y-2)^2/4-(x-1)^2/1-1)=0 [-20.43, 20.11, -9, 11.28]}

#### Answer:

**Standard form of vertical hyperbola equation is**

#### Explanation:

The standard form of equation of vertical hyperbola is

Therefore, the standard form of vertical hyperbola equation

is

graph{y^2-4 y -4 x^2+ 8 x -4=0 [-40, 40, -20, 20]} [Ans]