# How do you write an equation for a circle with center in quadrant two, Radius 3, Tangent to y-axis at (0,4)?

##### 1 Answer

Nov 15, 2016

#### Explanation:

As it is tangent to

the center is

Hence equation of circle is

i.e.

or

or

graph{x^2+y^2+6x-8y+16=0 [-8.78, 4.56, -0.8, 5.9]}