How do you write an equation for a circle with Centre at (-1,- 6) with radius 1/3?
The standard form of the equation of a circle is.
where (a ,b) are the coordinates of the centre and r, the radius.
here a = -1 , b = -6 and r
Substitute these values into the standard equation.
#rArr(x+1)^2+(y+6)^2=1/9" is the equation of the circle"#